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prior analytics-第33章

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it is true。 The terms are alike in both; and the premisses of both are



taken in the same way。 For example if A belongs to all B; C being



middle; then if it is supposed that A does not belong to all B or



belongs to no B; but to all C (which was admitted to be true); it



follows that C belongs to no B or not to all B。 But this is



impossible: consequently the supposition is false: its contradictory



then is true。 Similarly in the other figures: for whatever moods admit



of conversion admit also of the reduction per impossibile。



  All the problems can be proved per impossibile in all the figures;



excepting the universal affirmative; which is proved in the middle and



third figures; but not in the first。 Suppose that A belongs not to all



B; or to no B; and take besides another premiss concerning either of



the terms; viz。 that C belongs to all A; or that B belongs to all D;



thus we get the first figure。 If then it is supposed that A does not



belong to all B; no syllogism results whichever term the assumed



premiss concerns; but if it is supposed that A belongs to no B; when



the premiss BD is assumed as well we shall prove syllogistically



what is false; but not the problem proposed。 For if A belongs to no B;



and B belongs to all D; A belongs to no D。 Let this be impossible:



it is false then A belongs to no B。 But the universal affirmative is



not necessarily true if the universal negative is false。 But if the



premiss CA is assumed as well; no syllogism results; nor does it do so



when it is supposed that A does not belong to all B。 Consequently it



is clear that the universal affirmative cannot be proved in the



first figure per impossibile。



  But the particular affirmative and the universal and particular



negatives can all be proved。 Suppose that A belongs to no B; and let



it have been assumed that B belongs to all or to some C。 Then it is



necessary that A should belong to no C or not to all C。 But this is



impossible (for let it be true and clear that A belongs to all C):



consequently if this is false; it is necessary that A should belong to



some B。 But if the other premiss assumed relates to A; no syllogism



will be possible。 Nor can a conclusion be drawn when the contrary of



the conclusion is supposed; e。g。 that A does not belong to some B。



Clearly then we must suppose the contradictory。



  Again suppose that A belongs to some B; and let it have been assumed



that C belongs to all A。 It is necessary then that C should belong



to some B。 But let this be impossible; so that the supposition is



false: in that case it is true that A belongs to no B。 We may



proceed in the same way if the proposition CA has been taken as



negative。 But if the premiss assumed concerns B; no syllogism will



be possible。 If the contrary is supposed; we shall have a syllogism



and an impossible conclusion; but the problem in hand is not proved。



Suppose that A belongs to all B; and let it have been assumed that C



belongs to all A。 It is necessary then that C should belong to all



B。 But this is impossible; so that it is false that A belongs to all



B。 But we have not yet shown it to be necessary that A belongs to no



B; if it does not belong to all B。 Similarly if the other premiss



taken concerns B; we shall have a syllogism and a conclusion which



is impossible; but the hypothesis is not refuted。 Therefore it is



the contradictory that we must suppose。



  To prove that A does not belong to all B; we must suppose that it



belongs to all B: for if A belongs to all B; and C to all A; then C



belongs to all B; so that if this is impossible; the hypothesis is



false。 Similarly if the other premiss assumed concerns B。 The same



results if the original proposition CA was negative: for thus also



we get a syllogism。 But if the negative proposition concerns B;



nothing is proved。 If the hypothesis is that A belongs not to all



but to some B; it is not proved that A belongs not to all B; but



that it belongs to no B。 For if A belongs to some B; and C to all A;



then C will belong to some B。 If then this is impossible; it is



false that A belongs to some B; consequently it is true that A belongs



to no B。 But if this is proved; the truth is refuted as well; for



the original conclusion was that A belongs to some B; and does not



belong to some B。 Further the impossible does not result from the



hypothesis: for then the hypothesis would be false; since it is



impossible to draw a false conclusion from true premisses: but in fact



it is true: for A belongs to some B。 Consequently we must not



suppose that A belongs to some B; but that it belongs to all B。



Similarly if we should be proving that A does not belong to some B:



for if 'not to belong to some' and 'to belong not to all' have the



same meaning; the demonstration of both will be identical。



  It is clear then that not the contrary but the contradictory ought



to be supposed in all the syllogisms。 For thus we shall have necessity



of inference; and the claim we make is one that will be generally



accepted。 For if of everything one or other of two contradictory



statements holds good; then if it is proved that the negation does not



hold; the affirmation must be true。 Again if it is not admitted that



the affirmation is true; the claim that the negation is true will be



generally accepted。 But in neither way does it suit to maintain the



contrary: for it is not necessary that if the universal negative is



false; the universal affirmative should be true; nor is it generally



accepted that if the one is false the other is true。







                                12







  It is clear then that in the first figure all problems except the



universal affirmative are proved per impossibile。 But in the middle



and the last figures this also is proved。 Suppose that A does not



belong to all B; and let it have been assumed that A belongs to all C。



If then A belongs not to all B; but to all C; C will not belong to all



B。 But this is impossible (for suppose it to be clear that C belongs



to all B): consequently the hypothesis is false。 It is true then



that A belongs to all B。 But if the contrary is supposed; we shall



have a syllogism and a result which is impossible: but the problem



in hand is not proved。 For if A belongs to no B; and to all C; C



will belong to no B。 This is impossible; so that it is false that A



belongs to no B。 But though this is false; it does not follow that



it is true that A belongs to all B。



  When A belongs to some B; suppose that A belongs to no B; and let



A belong to all C。 It is necessary then that C should belong to no



B。 Consequently; if this is impossible; A mus
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